Mayday Mystery Octaves Solved
(Select image to see a real Shuriken)
"The octave, the simplest and most perfect consonance of all..." - Sir James Jeans
The theme to this announcement is "octave." The eight Hebrew letters around the outside of the 8-pointed star, are actually numbers. The large white Hebrew letter "chet" in the middle of the star is also a number. Chet is the eighth letter of the Hebrew alphabet. At first appearance, we would assign the natural or standard number equivalents for each Hebrew letter as shown below (Chet=8, Waw or Vav=6, Daleth=4, Beth=2, Sadhe=90, Gimel=3, Yod=10, Samech=60, and Ayin=70).
There does appear to be a pattern on the right side of the star where 70-60=10 and on the left side of the star where 6-4=2. However, the pattern does not make sense throughout the star. Add up all nine numbers to get 253. This number is also not significant with relation to the "octave" theme. There are several other Hebrew gematria systems of which one fits perfectly with the "octave" theme.
The above star uses the AT BASH Hebrew gematria numbering system. In AT BASH, the normal Hebrew counting system is used, except in reverse, where the last letter of the alphabet (Tav) equals "1" and the first letter (Aleph) equals 400.
AT BASH was a simple coding system used by the Essenes in many of their transcriptions of the Hebrew texts that were found within the Qumran caves in Israel from the year 1947 and onward.Add up all the numbers in the star (Chet=60 + Waw or Vav=80 + Daleth=100 + Beth=300 + Sadhe=5 + Gimel=200 + Yod=40 + Samech=8 + Ayin=7) to get 800. 800 represents 100 octaves (100x8=800). Converting 100 decimal to octal equals 144 (12x12) or (8x18). Make 100 an octal number, then convert it back to decimal to get 64 (8x8). Notice the play on words between octal and octave.
In western music, an octave actually contains 12 half steps (tones), but only eight notes are played to complete the octave scale. A major scale could be made up of the following notes and steps between the notes: C-(1)-D-(1)-E-(.5)-F-(1)-G-(1)-A-(1)-B-(.5)-C. A minor scale (more somber sounding) could be A-(1)-B-(.5)-C-(1)-D-(1)-E-(.5)-F-(1)-G-(1)-A.
The picture in the 95-Dec6 announcement on the left shows twelve ninja weapons: 1 sword and 11 stars. Let's see what happens if we square each of the numbers, add the squared numbers for each row, then add up all the squared numbers to get a grand total.12^2 = 144
[7^2=49 + 6^2=36 + 5^2=25 + 4^2=16 + 3^2=9 + 2^2=4 + 1^2=1] = 140
8^2 = 64
[11^2=121 + 10^2=100 + 9^2 = 81] = 302
[144 + 140 + 64 + 302] = 650.
Let's look at the sub-totals and total number closer:
864 octal can be broken down further as: 8+6+4=18. 18 decimal = 12 hex, 22 octal, and 33 pental.
In the picture, if you add together all the squared numbers for the weapons that line up vertically in the center (12^2=144 + 4^2=16 + 8^2=64 + 10^=100) you get 324 decimal that equals to 144 (12x12) or (8x18) hex.
Notice under the picture there are a couple references to "VIDE: 2^d from right (ADW, 5/1/95)" and to "ADW, 5/1/88, #4". These are clues to make all the numbers (1-12) exponents of 2, then use the CLAVIS key to reduce the numbers to a single number. Here is a particular method that works nicely to show how the reduction of the numbers relates directly to the "octave" theme of the announcement. Keep in mind that octaves are mutliples of eight, yet based on the number 12 (12 half steps within an octave).
First, assign the numbers one through 12 as exponents of the number two (2^1, 2^2, ..., 2^12). Second, resolve the numbers (2^1=2, 2^2=4, ..., 2^12=4096). Third, multiply the exponent of the original number times its resolved number (1x2=2, 2x4=8, ..., 12x4096=49152). Finally, reduce all the numbers to a single number in a descending triangular pattern.
Keeping in tune with the "octave" theme of this announcement, make a new chart (see below) with the numbers from the above chart that are evenly divisible by eight.
Notice that the above chart starts with the number eight at the top right of the triangle, and ends with 88 at the bottom of the triangle. Now divide all the numbers by eight, then rotate the chart counter-clockwise to get the following chart.
The above chart, beginning with numbers 1 to 11 for the first row, resolves down to the number 6144. Divide this number three times by 8 to end up with 12.
6144/8 = 768, 768/8 = 96, 96/8 = 12
Once again we derive at the number 12, and we also see how the number 8 relates harmoniously with 12. Combine the three eights that were used to divide 6144 to get 12, into 888. 888 is the Greek gematria number for the Greek name of Jesus (IHSOUS).
For fun, take the number 6144 and turn it into 6x144 that equals 864. Remember the breakdown of 864 from above?
Make a new chart (see below) from the bottom seven rows of the previous chart. Count how many times you can find the number 12 and 144. You might notice that this small chart contains nearly all the key numbers used throughout the ADW announcements [3 (occurances of 12 and 144), 7 (rows), 12, and 144].
Notice that the above chart of seven rows is the next group of numbers from the previous chart of eleven rows that can be evenly divided by eight. See the following chart.
Now find the next set of numbers that can be evenly divided by eight. Go ahead and divide them by eight to make the following chart.
Finally, the bottom number (96) in the previous chart can be evenly divided by eight to get twelve.
This site is sponsored by Borders Chess Club
www.BordersChess.org/Octaves.htm
modified 2006.04.14
