Mayday Mystery (May 01, 2001) #1947

If you add up all the Pi numbers listed in the May 01, 2001 announcement, not including the addendum, you get 1947. Everyone knows the importance of the year 1947 as being the year the first Dead Sea Scrolls were found. See a coin that commemorates the Qumran Cave scrolls:

http://www.borderschess.org/Sheqalim.htm

When dealing with numbers found in the ADW (Arizona Daily Wildcat) announcements, they could be in hex, octal, decimal, or binary. The fun is knowing when to convert the numbers from one base to another. For now, let's take the number 1947. Is it decimal? Not really. Let's make it a hex number, then convert the hex number to decimal: 1947 hex = 6471 dec. You wouldn't think 6471 has anything to do with the announcement until you list all the occurances of each individual PI number that makes up the large square.

3 (71) = 213
1 (50) =   50
4 (71) = 284
1 (64) =   64
5 (71) = 355
9 (50) = 450
2 (71) = 142
6 (64) = 384
           1942
              +5 (Five Pi numbers [53589] listed vertically below the cross.)
           1947

Multiplying all the digits of 53589 (5*3*5*8*9) equals 5400. By subtracting 3760 (Jewish Calendar years) from 5400, we get 1640 dec (end of Reformation) that equals to 668 hex. 668 is a major key number in the ADW announcements.

Notice the occurances for several of the Pi numbers are either 64, 71, or 50. You'll see later how we get the number 50.

If we change 6471 decimal to 6471 octal, then convert 6471 octal back to decimal, we get 3385. The ADW announcement creator(s) also likes to add all the digits of a number, multiply all the digits, factorialize the entire number, or factorialize each digit of a number and add them together to derive at new numbers.

If we multiply all the digits of 3385 (3*3*8*5), we get 360 dec. Factorializing and adding each digit of 3385 (3!+3!+8!+5!) equals 40452. Factorialize 40452, not including the zero, (4!+4!+5!+2!) equals 170. 170 oct = 120 dec.

Factorialize 120 (120!) and we end up with a 199 digit number beginning with 668. The last 196 digits fit perfectly in a 14x14 grid square. For more information about 668, see:

http://www.borderschess.org/668.htm

The 14x14 grid square for 120!, also known as Box 668 in the announcements, equals to 196 digits. 196 hex = 406 dec. 406 hex = 2006 oct, our current year.

The last 28 digits in the 14x14 box are zeros. Therefore, if we subtract 28 from 196 we get 168 (another number used repeatedly in the announcements). 168 dec = 250 oct (hence the 2 - 50 occurances of Pi numbers 1 and 9 in the first announcement). 168 hex = 360 dec (returning full circle back to 360).

360 hex = 864 dec and 1540 oct (numbers you may also find in the announcements).

144 dec = 90 hex and 220 oct (also used in the announcements).

The Addendum announcement references 695 that is an actual Episcopal hymn number previously mentioned in another post. 695 = 1267 oct. 1267 is the year Roger Bacon sent his three great works on academia (Opus Majus, Opus Minus, and Opus Tertium) to the pope. It is also the birth date of Giotte, the Father of the Renaissance (Rebirth). See my comments about Roger in the Dec 7, 2005 posting:

http://www.maydaymystery.org/mayday/texts/05-dec7.html

The 695 hymn, "By gracious powers so wonderfully sheltered," by F. Pratt Green and Dietrich Bonhoeffer, has a metric value (meter) of 11 10 11 10 in decimal. If we look at those numbers as binary, we get 11 10 11 10 ( 3, 2, 3, 2) or 1110 1110 (14, 14) or 11101110 (238). A case could be made for all of these numbers being used in these announcements. (14, 14) represents the 14x14 grid square of the 120! (668) number, while 238 represents the first uranium number listed directly under the 70 pi numbers in the Addendum. There are two sets of 70 pi numbers listed with 9 pi numbers missing from both lists. 164062862 missing digits in the first list add up to 35, while 081284811 missing digits in the last list add up to 33.

The logic math problem shown in the Addendum within two rectangles (level two, no doubt), is a similar exercise in using hex, decimal, octal, or the results of the binary (01) numbers. Each number has a couple missing numbers, hence the puzzle to be solved. The top number (dividend): 10102--892 occurs at the 91,155,441 decimal digit of Pi, counting from the first digit after the decimal point, and not including the beginning "3.". The actual number is 1010294892.

The bottom number (divisor): 014(01)--76 is another number that should be found in Pi. The (01) could be a reference to a binary number as listed in the 85-May1 and 86-May1 announcements (10100111111111001). This number equals 86009 dec or 247771 oct. 04186009 is listed three times in the first 200 million decimal digits of Pi. The number on the right is 24--76. It is interesting how close this number is to the octal 247771. (01) binary could also just be the number "1" decimal. There are dozens of 0141??76 numbers listed in the first 200 million decimal digits of Pi. Remember that the numbers in the logic puzzle could be from any or all of the aforementioned base number systems.

Here are a couple more conversions, especially for the number 120:

120 dec = 78 hex = 170 oct

120 hex (2*60) = 288 dec (2*144) = 440 oct (2*220) (440 hz and/or 220 hz is the note "A" in music, and is the tone I use for tuning my instruments.)

120 oct = 80 dec = 50 hex (notice the number 50 again).

The rack of billiard balls (15 balls total) shown in the 87-Apr8 and 88-May1 announcements, add up to 120). There are over 1.3 trillion combinations of those 15 balls that can be placed in the rack. I will write more at a later time about how to use these rack of balls, their number sequences, and various combinations for solving cryptic cipher messages.

I'm beginning to get an overall impression that the ADW announcements, though highly academic in nature with lots of fun logic problems, are also laying down a foundation for the coming events of the New Jerusalem. Read more about the New Jerusalem at:

http://www.apocalipsis.org/t21-new-jerusalem.htm

The New Jerusalem (cubic in nature) - brings together the OT (12 tribes of Israel) and the NT (12 Apostles of Jesus) along with all other faithful believers. See my simple mathematical art interpretation below:

© Dan Thomasson - March 25, 2006